SSC নন টিচিং স্টাফ নিয়োগ পরীক্ষার গণিত বিষয়ের কিছু প্রশ্নের উত্তর (সরল সুদ )
প্রশ্ন 51: Principal = ₹2000, Rate = 6% per annum, Time = 2.5 years
Solution:
SI = (P × R × T) / 100
= (2000 × 6 × 2.5) / 100
= (2000 × 15) / 100 = ₹300
প্রশ্ন 52: Principal = ₹1800, Rate = 8% per annum, Time = 3 years
Solution: SI = (1800 × 8 × 3) / 100 = ₹432
প্রশ্ন 53: SI = ₹240, Rate = 10% per annum, Time = 2 years. Find the Principal.
Solution:
SI = (P × R × T)/100 ⇒ 240 = (P × 10 × 2)/100
⇒ 240 = (20P)/100 ⇒ P = ₹1200
প্রশ্ন 54: Find the rate if SI = ₹300, P = ₹1500, T = 4 years
Solution:
SI = (P × R × T)/100 ⇒ 300 = (1500 × R × 4)/100
⇒ 300 = 60R ⇒ R = 5%
প্রশ্ন 55: Find the time if SI = ₹500, P = ₹2500, R = 5%
Solution:
SI = (P × R × T)/100 ⇒ 500 = (2500 × 5 × T)/100
⇒ 500 = 125T ⇒ T = 4 years
প্রশ্ন 56: A sum of ₹1600 amounts to ₹1840 in 3 years. Find the rate.
Solution:
SI = 1840 - 1600 = ₹240
SI = (1600 × R × 3)/100 ⇒ 240 = 48R ⇒ R = 5%
প্রশ্ন 57: ₹1200 invested at 10% per annum for how many years will yield ₹300?
Solution:
SI = (1200 × 10 × T)/100 = 120T/100 = ₹300
⇒ T = 2.5 years
প্রশ্ন 58: What is the SI on ₹2400 at 12.5% for 1.5 years?
Solution:
SI = (2400 × 12.5 × 1.5)/100
= (2400 × 18.75)/100 = ₹450
প্রশ্ন 59: ₹1500 earns ₹270 SI in 3 years. What is the rate?
Solution: SI = (1500 × R × 3)/100 = 270 ⇒ 45R = 270 ⇒ R = 6%
প্রশ্ন 60: In how many years will ₹1000 earn ₹200 at 8%?
Solution: SI = (1000 × 8 × T)/100 = 80T ⇒ 80T = 200 ⇒ T = 2.5 years
প্রশ্ন 61: Principal = ₹2500, Rate = 4%, Time = 2 years
Solution: SI = (2500 × 4 × 2)/100 = ₹200
প্রশ্ন 62: Find principal if SI = ₹480, R = 8%, T = 3 years
Solution:
SI = (P × R × T)/100 ⇒ 480 = (P × 8 × 3)/100
⇒ P = (480 × 100)/(24) = ₹2000
প্রশ্ন 63: If ₹2000 gives ₹600 in 5 years, what is the rate?
Solution: SI = 600 = (2000 × R × 5)/100 ⇒ 100R = 600 ⇒ R = 6%
প্রশ্ন 64: Amount = ₹1260, Principal = ₹1200, Time = 3 years. Find rate.
Solution:
SI = 1260 - 1200 = ₹60
SI = (1200 × R × 3)/100 ⇒ 36R = 60 ⇒ R = 1.67%
প্রশ্ন 65: Principal = ₹3200, Rate = 5.5%, Time = 2 years
Solution: SI = (3200 × 5.5 × 2)/100 = ₹352
প্রশ্ন 66: SI = ₹144, Rate = 6%, Time = 3 years. Find P.
Solution: 144 = (P × 6 × 3)/100 ⇒ 18P/100 = 144 ⇒ P = ₹800
প্রশ্ন 67: Find the SI on ₹5000 at 7.5% for 4 years
Solution: SI = (5000 × 7.5 × 4)/100 = ₹1500
প্রশ্ন 68: Find rate if SI = ₹1000, P = ₹5000, T = 5 years
Solution: 1000 = (5000 × R × 5)/100 ⇒ 250R = 1000 ⇒ R = 4%
প্রশ্ন 69: A man lent ₹1500 for 2 years and got ₹180 as interest. Find rate.
Solution: 180 = (1500 × R × 2)/100 ⇒ 30R = 180 ⇒ R = 6%
প্রশ্ন 70: Principal = ₹10000, Rate = 9%, Time = 1 year 6 months
Solution:
T = 1.5 years
SI = (10000 × 9 × 1.5)/100 = ₹1350
প্রশ্ন 71: ₹500 earns ₹50 in 2 years. Find rate.
Solution: 50 = (500 × R × 2)/100 ⇒ 10R = 50 ⇒ R = 5%
প্রশ্ন 72: SI = ₹375, P = ₹2500, T = 3 years. Find rate.
Solution: 375 = (2500 × R × 3)/100 ⇒ 75R = 375 ⇒ R = 5%
প্রশ্ন 73: ₹800 at 10% for how long will give ₹200?
Solution: SI = (800 × 10 × T)/100 = 80T ⇒ 80T = 200 ⇒ T = 2.5 years
প্রশ্ন 74: A sum doubles in 10 years. Find rate.
Solution:
SI = P (since amount is 2P), Time = 10 years
⇒ P = (P × R × 10)/100 ⇒ 10R = 100 ⇒ R = 10%
প্রশ্ন 75: Find interest earned on ₹6000 at 8.5% for 3 years
Solution: SI = (6000 × 8.5 × 3)/100 = ₹1530